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交换变量
x=6 y=5 x,y=y,x print x,y >>>5,6
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计算技巧
# 2的5次方 print 2**5 >>>32
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两个列表同时迭代
nfc = ["Packers", "49ers"] afc = ["Ravens", "Patriots"] for teama, teamb in zip(nfc, afc): print teama + " vs. " + teamb >>> Packers vs. Ravens >>> 49ers vs. Patriots
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带索引的列表迭代
teams = ["Packers", "49ers", "Ravens", "Patriots"] for index, team in enumerate(teams): print index, team >>> 0 Packers >>> 1 49ers >>> 2 Ravens >>> 3 Patriots
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列表推导
已知一个列表,刷选出偶数列表方法:
numbers = [1,2,3,4,5,6] even = [] for number in numbers: if number%2 == 0: even.append(number)
用下面方法写:
numbers = [1,2,3,4,5,6] even = [number for number in numbers if number%2 == 0]
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将列表转换成字符串
teams = ["Packers", "49ers", "Ravens", "Patriots"] print ", ".join(teams) >>> 'Packers, 49ers, Ravens, Patriots'
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获取子列表
x = [1,2,3,4,5,6] #前3个 print x[:3] >>> [1,2,3] #中间4个 print x[1:5] >>> [2,3,4,5] #最后3个(方法1) print x[-3:] >>> [4,5,6] #最后3个(方法2) print x[3:7] >>> [4,5,6] #奇数项 print x[::2] >>> [1,3,5] #偶数项 print x[1::2] >>> [2,4,6]
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集合
用到Counter库
from collections import Counter print Counter("hello") >>> Counter({'l': 2, 'h': 1, 'e': 1, 'o': 1})
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迭代工具
和collections库一样,还有一个库叫itertools
from itertools import combinations teams = ["Packers", "49ers", "Ravens", "Patriots"] for game in combinations(teams, 2): print game >>> ('Packers', '49ers') >>> ('Packers', 'Ravens') >>> ('Packers', 'Patriots') >>> ('49ers', 'Ravens') >>> ('49ers', 'Patriots') >>> ('Ravens', 'Patriots')
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负数索引切割列表
>>> a = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] >>> a[-4:-2] [7, 8]